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Gold/Mining/Energy : Le coin des prospecteurs

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To: Chileno80 who wrote (30652)11/5/2021 6:06:26 PM
From: jpthoma11 Recommendation

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riversides

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Ton exemple ne fonctionne pas (impossible), mais prenons 10m @12 g/t incluant un 0.5m @ 200g/t.

Alors le 10m a un facteur métal total de 120 (10X12) et le 0,5m de 100 (0,5X200). Donc le 9,5m restant a un facteur métal de 20 (120-100), soit environ 2,1g/t (20÷9,5).

Et ça, ils ne le publient pas toujours, il faut que tu le calcules.
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